圆月山庄资源网 Design By www.vgjia.com

复制代码 代码如下:
#!c:\python27\python.exe
# -*- coding: utf-8 -*-

import os
import re

from os import path
from shutil import rmtree

DEL_DIRS = None
DEL_FILES = r'(.+?\.pyc$|.+?\.pyo$|.+?\.log$)'

def del_dir(p):
    """Delete a directory."""
    if path.isdir(p):
        rmtree(p)
        print('D : %s' % p)

def del_file(p):
    """Delete a file."""
    if path.isfile(p):
        os.remove(p)
        print('F : %s' % p)

def gen_deletions(directory, del_dirs=DEL_DIRS, del_files=DEL_FILES):
    """Generate deletions."""
    patt_dirs = None if del_dirs == None else re.compile(del_dirs)
    patt_files = None if del_files == None else re.compile(del_files)

    for root, dirs, files in os.walk(directory):
        if patt_dirs:
            for d in dirs:
                if patt_dirs.match(d):
                    yield path.join(root, d)
        if patt_files:
            for f in files:
                 if patt_files.match(f):
                    yield path.join(root, f)

def confirm_deletions(directory):
    import Tkinter
    import tkMessageBox

    root = Tkinter.Tk()
    root.withdraw()
    res = tkMessageBox.askokcancel("Confirm deletions?",
        "Do you really wish to delete?\n\n"
        "Working directory:\n%s\n\n"
        "Delete conditions:\n(D)%s\n(F)%s"
        % (directory, DEL_DIRS, DEL_FILES))
    if res:
        print('Processing...')
        m, n = 0, 0
        for p in gen_deletions(directory):
            if path.isdir(p):
                del_dir(p)
                m += 1
            elif path.isfile(p):
                del_file(p)
                n += 1
        print('Clean %d dirs and %d files.' % (m, n))
        root.destroy()
    else:
        print('Canceled.')
        root.destroy()

    root.mainloop()

if __name__ == '__main__':
    import sys
    argv = sys.argv
    directory = argv[1] if len(argv) >= 2 else os.getcwd()
    confirm_deletions(directory)
    # import subprocess
    # subprocess.call("pause", shell=True)

标签:
python2.7,删除文件夹

圆月山庄资源网 Design By www.vgjia.com
广告合作:本站广告合作请联系QQ:858582 申请时备注:广告合作(否则不回)
免责声明:本站文章均来自网站采集或用户投稿,网站不提供任何软件下载或自行开发的软件! 如有用户或公司发现本站内容信息存在侵权行为,请邮件告知! 858582#qq.com
圆月山庄资源网 Design By www.vgjia.com