圆月山庄资源网 Design By www.vgjia.com

1、cube:生成多维数据集,包含各维度可能组合的交叉表格,使用with 关键字连接 with cube

根据需要使用union all 拼接

判断 某一列的null值来自源数据还是 cube 使用GROUPING关键字

GROUPING([档案号]) = 1 : null值来自cube(代表所有的档案号)
GROUPING([档案号]) = 0 : null值来自源数据

举例:

SELECT * INTO ##GET
FROM 
  (SELECT *
    FROM ( SELECT
      CASE
      WHEN (GROUPING([档案号]) = 1) THEN
      '合计'
      ELSE [档案号]
      END AS '档案号',
      CASE
      WHEN (GROUPING([系列]) = 1) THEN
      '合计'
      ELSE [系列]
      END AS '系列',
      CASE
      WHEN (GROUPING([店长]) = 1) THEN
      '合计'
      ELSE [店长]
      END AS '店长', SUM (剩余次数) AS '总剩余',
      CASE
      WHEN (GROUPING([店名]) = 1) THEN
      '合计'
      ELSE [店名]
      END AS '店名'
    FROM ##PudianCard
    GROUP BY [档案号], [店名], [店长], [系列]
    WITH cube
    HAVING GROUPING([店名]) != 1
        AND GROUPING([档案号]) = 1 --AND GROUPING([系列]) = 1 ) AS M
    UNION
    ALL 
      (SELECT *
        FROM ( SELECT
          CASE
          WHEN (GROUPING([档案号]) = 1) THEN
          '合计'
          ELSE [档案号]
          END AS '档案号',
          CASE
          WHEN (GROUPING([系列]) = 1) THEN
          '合计'
          ELSE [系列]
          END AS '系列',
          CASE
          WHEN (GROUPING([店长]) = 1) THEN
          '合计'
          ELSE [店长]
          END AS '店长', SUM (剩余次数) AS '总剩余',
          CASE
          WHEN (GROUPING([店名]) = 1) THEN
          '合计'
          ELSE [店名]
          END AS '店名'
        FROM ##PudianCard
        GROUP BY [档案号], [店名], [店长], [系列]
        WITH cube
        HAVING GROUPING([店名]) != 1
            AND GROUPING([店长]) != 1 ) AS P )
        UNION
        ALL 
          (SELECT *
            FROM ( SELECT
              CASE
              WHEN (GROUPING([档案号]) = 1) THEN
              '合计'
              ELSE [档案号]
              END AS '档案号',
              CASE
              WHEN (GROUPING([系列]) = 1) THEN
              '合计'
              ELSE [系列]
              END AS '系列',
              CASE
              WHEN (GROUPING([店长]) = 1) THEN
              '合计'
              ELSE [店长]
              END AS '店长', SUM (剩余次数) AS '总剩余',
              CASE
              WHEN (GROUPING([店名]) = 1) THEN
              '合计'
              ELSE [店名]
              END AS '店名'
            FROM ##PudianCard
            GROUP BY [档案号], [店名], [店长], [系列]
            WITH cube
            HAVING GROUPING([店名]) != 1
                AND GROUPING([店长]) != 1 ) AS W )
            UNION
            ALL 
              (SELECT *
                FROM ( SELECT
                  CASE
                  WHEN (GROUPING([档案号]) = 1) THEN
                  '合计'
                  ELSE [档案号]
                  END AS '档案号',
                  CASE
                  WHEN (GROUPING([系列]) = 1) THEN
                  '合计'
                  ELSE [系列]
                  END AS '系列',
                  CASE
                  WHEN (GROUPING([店长]) = 1) THEN
                  '合计'
                  ELSE [店长]
                  END AS '店长', SUM (剩余次数) AS '总剩余',
                  CASE
                  WHEN (GROUPING([店名]) = 1) THEN
                  '合计'
                  ELSE [店名]
                  END AS '店名'
                FROM ##PudianCard
                GROUP BY [档案号], [店名], [店长], [系列]
                WITH cube
                HAVING GROUPING([店名]) = 1
                    AND GROUPING([店长]) = 1
                    AND GROUPING([档案号]) = 1 ) AS K ) ) AS T

2、rollup:功能跟cube相似

3、将某一列的数据作为列名,动态加载,使用存储过程,拼接字符串

DECLARE @st nvarchar (MAX) = '';SELECT @st =@st + 'max(case when [系列]=''' + CAST ([系列] AS VARCHAR) + ''' then [总剩余] else null end ) as [' + CAST ([系列] AS VARCHAR) + '],'
FROM ##GET
GROUP BY [系列]; print @st;

4、根据某一列分组,分别建表

SELECT
				'select ROW_NUMBER() over(order by [卡项] desc) as [序号], [会员],[档案号],[卡项],[剩余次数],[员工],[店名] into ' + ltrim([店名]) + ' from 查询 where [店名]=''' + [店名] + ''' ORDER BY [卡项] desc'
		FROM
			查询
		GROUP BY
			[店名]

总结

以上就是本文关于SQLserver中cube:多维数据集实例详解的全部内容,希望对大家有所帮助。感兴趣的朋友可以继续参阅:MYSQL子查询和嵌套查询优化实例解析、几个比较重要的MySQL变量、ORACLE SQL语句优化技术要点解析等,有什么问题可以随时留言,小编会及时回复大家的。感谢各位对本站的支持!

标签:
sql,server,cube,sqlserver,cube

圆月山庄资源网 Design By www.vgjia.com
广告合作:本站广告合作请联系QQ:858582 申请时备注:广告合作(否则不回)
免责声明:本站文章均来自网站采集或用户投稿,网站不提供任何软件下载或自行开发的软件! 如有用户或公司发现本站内容信息存在侵权行为,请邮件告知! 858582#qq.com
圆月山庄资源网 Design By www.vgjia.com

《魔兽世界》大逃杀!60人新游玩模式《强袭风暴》3月21日上线

暴雪近日发布了《魔兽世界》10.2.6 更新内容,新游玩模式《强袭风暴》即将于3月21 日在亚服上线,届时玩家将前往阿拉希高地展开一场 60 人大逃杀对战。

艾泽拉斯的冒险者已经征服了艾泽拉斯的大地及遥远的彼岸。他们在对抗世界上最致命的敌人时展现出过人的手腕,并且成功阻止终结宇宙等级的威胁。当他们在为即将于《魔兽世界》资料片《地心之战》中来袭的萨拉塔斯势力做战斗准备时,他们还需要在熟悉的阿拉希高地面对一个全新的敌人──那就是彼此。在《巨龙崛起》10.2.6 更新的《强袭风暴》中,玩家将会进入一个全新的海盗主题大逃杀式限时活动,其中包含极高的风险和史诗级的奖励。

《强袭风暴》不是普通的战场,作为一个独立于主游戏之外的活动,玩家可以用大逃杀的风格来体验《魔兽世界》,不分职业、不分装备(除了你在赛局中捡到的),光是技巧和战略的强弱之分就能决定出谁才是能坚持到最后的赢家。本次活动将会开放单人和双人模式,玩家在加入海盗主题的预赛大厅区域前,可以从强袭风暴角色画面新增好友。游玩游戏将可以累计名望轨迹,《巨龙崛起》和《魔兽世界:巫妖王之怒 经典版》的玩家都可以获得奖励。